No. It is multi-tasking and time-sharing



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送交者: xinku 于 2006-2-20, 20:46:53:

回答: that sounded more realistics. This is basically an IBM batch 由 steven 于 2006-2-20, 20:42:22:

because there are multi processes running in memory. Some of them are outputing, which means they are not occupying CPU, some of them are calculating, which means they have to occupying CPU, and the others are waiting for the CPU. You have to deal with muliti process scheduling in this environment.



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