there isn't such a condition, your question too ambiguous.


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送交者: steven 于 2012-04-25, 19:41:34:

回答: 不好, 没有说明实数是 uncountable 由 sssa 于 2012-04-25, 16:27:54:

If your question could mean:,if there is a proper subset s of real number, and the cardinal of s is equal to the cardinal of real number, and is countable. That is a contradiction since the cardinal of real is alepth_1 assuming continuum hypothesis hold, which is not equal to alepth_0, the cardinal of integer.

If your question is: If there is a proper subset s of real, and the cardinal of s is aleph_0, than, the set of rational number, the set of integer, the set of algebraic number are all the same which is equal to integer, and your question is a tautology.




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