Analytical result：。。。。。。

送交者: LaoXiao 于 2010-01-21, 19:26:19:

Analytical result for "有重名的情况"：

Let N be the number of "字母" can be used for surname, the probability is

P(N) = [ n^3 + 6*n^2 + 11*n + 6 ] / [ 24*n^3 ]

P(26) = 0.05197

P(N) --> 1/24 when N --> infinite.

good one, though don't know how you derived. - Amsel (132 bytes) 2010-01-21, 19:45:12 (406763)
- The coef. var. of Uniform r.v. is relatively high. - LaoXiao (260 bytes) 2010-01-21, 20:35:40 (406790)
- 人家给出答案了你都还不明白，不愧是民科妄人呀 - wanxiang (75 bytes) 2010-01-21, 19:51:15 (406765)