because of the concurrency issues. Unless the algorithm
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送交者: ak70 于 2011-02-24, 02:33:08:
回答: why not? 由 steven 于 2011-02-24, 02:26:17:
is wait-free, I don't know how to measure it with big-O. If one uses locks, then in many cases, the latency is not so high, but lock-free (but not wait-free) algorithms seem to have higher latency in general and an execution could be delayed indefinitely.
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